Discussion:
TCP: Slow Start
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Kevin
2008-12-03 10:59:42 UTC
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the slides say (22.24) "If no timeout, slowly increase window size
(throughput) by 1 for each ack received"

Review session last night, Jon said:
"TCP Slow start - send packets exponentially increasing the window size
until we receive our first loss. Start at 1 packet and increase until we
hit a loss, then cut window size in half and continue increment from
there. rinse and repeat.

which one is right?
Arthur Klepchukov
2008-12-03 11:28:27 UTC
Permalink
I believe slowly increase / cut in half at the first loss is correct.
Post by Kevin
the slides say (22.24) "If no timeout, slowly increase window size
(throughput) by 1 for each ack received"
"TCP Slow start - send packets exponentially increasing the window size
until we receive our first loss. Start at 1 packet and increase until we
hit a loss, then cut window size in half and continue increment from
there. rinse and repeat.
which one is right?
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